one input in mex is not read correctly
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Abeera Tariq
il 2 Giu 2015
Commentato: Abeera Tariq
il 2 Giu 2015
This is the code for mex file I created. mex file reads one input matrix I perfectly fine. but the values of other input matrix X are not correct.. I am not getting what is the issue.. I have attached the mat file for X(A.mat) and I(I.mat). the input function call pattern is mex name(1,2,4,3,3,I',A);
void IDWT(double z[5],float X[20][4], double row,double col, double of,double nv,double S, double I[9][8])
{
for (i = 0; i < 20; i++){
for( j = 0 ; j <4 ; j++ ){
printf("%f-", X[i][j]);}
printf("\n");
}
for (i = 0; i < 9; i++){
for( j = 0 ; j <8 ; j++ ){
printf("%f-", I[i][j]);}
printf("\n");
}
printf("\n");
}
void mexFunction(int nlhs, mxArray *plhs[], int nrhs, const mxArray *prhs[])
{
//DECLARING ALL THE ARGUMENTS
double row; double col; double of; double nv; double S; double *I; float *X;
//DOUBLE PRECISION CORRESPONDANCE OF THE OUTPUT
double *Z;
row = mxGetScalar(prhs[0]);
col = mxGetScalar(prhs[1]);
of = mxGetScalar(prhs[2]);
nv = mxGetScalar(prhs[3]);
S = mxGetScalar(prhs[4]);
// SPECIAL CASE FOR ARRAYS
I= mxGetPr(prhs[5]);
X = mxGetPr(prhs[6]);
plhs[0] = mxCreateDoubleMatrix(1,nv,mxREAL); // I put nv=5 for input,keeping in mind the size of output
Z = mxGetPr(plhs[0]);
IDWT(Z,X,row,col, of, nv, S, I);
}
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James Tursa
il 2 Giu 2015
Modificato: James Tursa
il 2 Giu 2015
1) A.mat contains a double precision variable, but in your argument list you have X declared as a float (single precision). Change that float to double.
2) A.mat contains a 20x4 matrix. The memory layout of this matrices is column-ordered. I.e., the 1st column is in memory first, followed in memory by the 2nd column, followed in memory by the 3rd column, etc. But C 2D matrices are assumed to be in memory in row order. I.e., a [20][4] matrix in C would have the 1st row in memory first, followed in memory by the 2nd row, followed in memory by the 3rd row, etc. This is not going to match up with the MATLAB memory order. If you compare your printed output you will find that, e.g., A(2,1) does not match up with X[1][0] as you might have expected. You need to think of the [ ][ ] indexing as backwards from the MATLAB indexing in order to get things to work out properly. So either you need to pass in the transpose A' like you did with I', or you need to reverse the indexing in the C routine.
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