how to compare a line a of matrix with another ?

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hello, giving the following matrix :
matrix=[5 6 4;3 4 4;5 6 4;7 8 4;9 10 4;1 2 4];
I want to compare the first 2 elements of each rows and display a message if 2(or more) of them have the same elements
I tried to do it this way:
matrix=[5 6 4;3 4 4;5 6 4;7 8 4;9 10 4;1 2 4];
for i=1:size(matrix,1)
a=matrix(i,1);
for k=1:size(matrix,2)
b=matrix(k,2);
m1=[a b];
end
end
for i=1:size(matrix,1)
c=matrix(i,1);
for k=1:size(matrix,2)
d=matrix(k,2);
m2 =[c d];
end
end
if m2==m1
disp('YOU GOT IT !!');
end
matrix
I created 2 vectors m1 and m2 with the values of the first elements and then compare the vectors.
but I dont get any positve results.

Risposta accettata

dpb
dpb il 17 Giu 2015
>> if size(unique(matrix(:,1:2),'rows'),1)<size(matrix,1)
disp('Is at least one match')
else
disp('All unique')
end
Is match
>>
  5 Commenti
Paul Nanfah
Paul Nanfah il 22 Giu 2015
Modificato: Paul Nanfah il 22 Giu 2015
sry that the first command was not clear, I actualy meant the command "Is match" at the end of your code seems to be of no use, unless I am wrong.
dpb
dpb il 22 Giu 2015
Modificato: dpb il 23 Giu 2015
Oh, I see...actually, that's output from the command line, not a command at all (as is shown by it's not preceded by the prompt >> characters and isn't part of a continuing code block as the previous lines from if to the end). I initially had only that string as the disp argument for the match; I expanded it when pasting in the Answer by inserting the "at least one" phrase to make the resulting message more explicit but didn't do the same with the previous output so the two don't match...

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