# Break statements still result in the first condition breaking array element being shown - how can it be stopped from being generated?

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Thom on 3 Dec 2011
Just a little annoying that matlab throws up the value that breaks a condition in the case below - can the code below be changed to solve this please?
For example
A = [ 2 3 4 5 6 9 9 10] %(elements of A matches t)
for t = 1:8;
B(t) = 3*A(t);
if B(t) >= 24;
break
elseif B(t) <= 3;
break
end
end
end
I would like to get from this B = [6 9 12 15 18]- the last three exceed 24.
Instead I get B = [6 9 12 15 18 27]
How can the code be changed so that B(6) = 27 will not be printed?
Many Thanks!

Fangjun Jiang on 3 Dec 2011
One solution:
A = [ 2 3 4 5 6 9 9 10] %(elements of A matches t)
for t = 1:8;
B(t) = 3*A(t);
if B(t) >= 24 || B(t)<=3
B(t)=[];
break
end
end

Naz on 3 Dec 2011
As far as I understand, you don't care weather you reach the end of the A array or not. As soon as you hit the fist value that is out of (3 24) bound you want to break. Is that right? If so, then you can do the following:
A = [ 2 3 4 5 6 9 9 10] %(elements of A matches t)
for t = 1:length(A)
if 3*A(t) >= 24 || 3*A(t) <=3
break;
else
B(t) = 3*A(t);
end
end

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