how to fit a plane to my point cloud data and rotate it so that the plane is parallel to the x-y plane.

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Ubaldo Pantaleo
Ubaldo Pantaleo on 7 Aug 2015
Hi All,
I have a set of approximately 1 million (x,y,z) points collected through photogrammetric tecniques of seabeds. The seafloor is characterized by a slope. I would like to:
  1. fit a plane to my data;
  2. rotate my 3d point cloud so that the fitted plane is parallel to xy-plane;
  3. export the new 3d point cloud into .txt or .xyz file
i fit the plane in this way:
%%Loading data
%data = load('Coralligeno_outcrop.txt');
data = load('./input.dat');
x = data(:,1);
y = data(:,2);
z = data(:,3);
clear data;
%%Finds the mean plan
% Combine X,Y,Z into one array
XYZ = [x,y,z];
% column means. This will allow us to do the fit properly with no
% constant term needed. It is necessary to do it this way, as
% otherwise the fit would not be properly scale independent
cm = mean(XYZ,1);
% subtract off the column means
XYZ0 = bsxfun(@minus,XYZ,cm);
% The "regression" as a planar fit is now accomplished by SVD.
% This presumes errors in all three variables. In fact, it makes
% presumptions that the noise variance is the same for all the
% variables. Be very careful, as this fact is built into the model.
% If your goal is merely to fit z(x,y), where x and y were known
% and only z had errors in it, then this is the wrong way
% to do the fit.
[U,S,V] = svd(XYZ0,0);
% The singular values are ordered in decreasing order for svd.
% The vector corresponding to the zero singular value tells us
% the direction of the normal vector to the plane. Note that if
% your data actually fell on a straight line, this will be a problem
% as then there are two vectors normal to your data, so no plane fit.
% LOOK at the values on the diagonal of S. If the last one is NOT
% essentially small compared to the others, then you have a problem
% here. (If it is numerically zero, then the points fell exactly in
% a plane, with no noise.)
diag(S)
% Assuming that S(3,3) was small compared to S(1,1), AND that S(2,2)
% is significantly larger than S(3,3), then we are ok to proceed.
% See that if the second and third singular values are roughly equal,
% this would indicate a points on a line, not a plane.
% You do need to check these numbers, as they will be indicative of a
% potential problem.
% Finally, the magnitude of S(3,3) would be a measure of the noise
% in your regression. It is a measure of the deviations from your
% fitted plane.
% The normal vector is given by the third singular vector, so the
% third (well, last in general) column of V. I'll call the normal
% vector P to be consistent with the question notation.
P = V(:,3);
% The equation of the plane for ANY point on the plane [x,y,z]
% is given by
%
% dot(P,[x,y,z] - cm) == 0
%
% Essentially this means we subtract off the column mean from our
% point, and then take the dot product with the normal vector. That
% must yield zero for a point on the plane. We can also think of it
% in a different way, that if a point were to lie OFF the plane,
% then this dot product would see some projection along the normal
% vector.
%
% So if your goal is now to predict Z, as a function of X and Y,
% we simply expand that dot product.
%
% dot(P,[x,y,z]) - dot(P,cm) = 0
%
% P(1)*X + P(2)*Y + P(3)*Z - dot(P,cm) = 0
%
% or simply (assuming P(3), the coefficient of Z) is not zero...
Z_mp = (dot(P,cm) - P(1)*x - P(2)*y)/P(3);
i don't know how to do the translation
Any help or direction to appropriate answers would be very welcome.
Thanks in advance!
Ubi

Answers (2)

Matt J
Matt J on 7 Aug 2015
Edited: Matt J on 7 Aug 2015
i don't know how to do the translation
I assume you mean the rotation. You can use my AxelRot tool ( Download ).
u=cross(P/norm(P),[0,0,1]);
deg=asind(norm(u));
[XYZnew, R, t] = AxelRot(XYZ', deg, u, [0;0;0]);
  9 Comments
Tasha Tardieu
Tasha Tardieu on 4 Mar 2018
Hi Robert,
I have a very similar problem to yours where I have 3D data that I want to make horizontal. After you found the lowest plane of your point cloud, how did you use AxelRot and apply it to all of your points? It seems that I am still getting the same image before and after rotation. I have attached 2D images of the points for reference with respect to the z axis.
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Preetham Manjunatha
Preetham Manjunatha on 23 Jul 2021
Fit a oriented bounding box and obtain the orientation of that bounding box and invert the rotation matrix of the Euler angles. This will produce a re-orientated point cloud that is parallel to XY, YZ and XZ planes. If you need to rotate again, Eulaer angles [phi theta psi] can be used, for example [90 0 0] or [-90 0 0] and others. The program which does this can be downloaded at 3DspaceTile.
This program actually divides the 3D space, one can use the divisions as [1 1 1] in XYZ directions. Same program can reorient the point clouds to be parallel to XY, YZ and XZ planes. For the program requirements, please visit the GitHub page.
Hope this helps someone in future.

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