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Creating an efficient for loop

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Cary il 17 Ago 2015
Commentato: Star Strider il 17 Ago 2015
for i = 1:length(startIdx)
for j = 1:length(date(startIdx(i):cutoffIdx(i)))
k = date(startIdx(i):cutoffIdx(i));
warning('Not present')
Let's say i = 1:4. On the first pass through i, everything is fine. But when i = 2, I am overwriting the stored shortIdx data I created when i was 1. j is the length of each i, and k is the dates for each i. Where I get tripped up is the last part of the try statement
because when i turns to 2, j is reset to 1. So even though k is the correct set of dates for i, I am simply overwriting the shortIdx variable, instead of appending to it. Is there a way for me to solve this efficiently? Or do I need to create an independent for loop for each i? Thank you.

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Star Strider
Star Strider il 17 Ago 2015
I can’t run your code, but if ‘shortIdx’ is a single value (likely an index, considering the find call), one (probably the easiest) solution is to create a matrix out of ‘shortIdx’ so it increments with both ‘i’ and ‘j’:
shortIdx(i,j) = ...;
and then refer to it by both indices in your catch block.
  2 Commenti
Cary il 17 Ago 2015
Beautiful, Star. As always, thanks for your help!
Star Strider
Star Strider il 17 Ago 2015
As always, my pleasure!

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