plotting a polynomial function

How can I plot a polynomial function in MATLAB? for example:
89.9659+0.1110371T-0.001472155T^2+ 1.1E-5T^3-4.381E-8T^4+1E-10T^5

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mohammad
mohammad il 18 Giu 2012
Modificato: Walter Roberson il 23 Ott 2023
y_1 = @(x) -0.6729+4.8266*x-0.4855*x.^2+0.0312*x.^3
y_1 = function_handle with value:
@(x)-0.6729+4.8266*x-0.4855*x.^2+0.0312*x.^3
x_1 = 0:0.1:33.5;
plot(x_1,y_1(x_1))

3 Commenti

What is ment by x_1 = 0:0.1:33.5;
Guck mal hier Breitenbach:
doc colon
Sorry not German or Dutch, my surname is Afrikaanse. so I presume you ment "look here", we write it as "Kyk heir"(said Cake Hirr(like the i in his with a pronounced roll of the r). So the zero means that our number set begins at zero and ends at 33.5, and we get from zero to 33.5 by adding incraments of 0.1? Is this correct?

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Più risposte (5)

Rubén Lumbiarres
Rubén Lumbiarres il 13 Set 2018
Modificato: Walter Roberson il 15 Set 2018
x=-5:.1:5;
p=[1 -1 -11 9 18] % polynomial function
plot(x,polyval(p,x))
grid on

1 Commento

Thanks!
I made it one step easier, with no need to specify spacing...
fplot(@(x) polyval(p,x), [-5 5])
grid on

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Fangjun Jiang
Fangjun Jiang il 14 Dic 2011
Of course ezplot(), but you need to fix your formula.
ezplot('89.9659+0.1110371*T-0.001472155*T^2+ 1.1E-5*T^3-4.381E-8*T^4+1E-10*T^5')

1 Commento

mohammad
mohammad il 14 Dic 2011
Thanks Fangjun, how can I plot from T=100 to T=1000?
When I use xlim([100 1000]), It doesn't plot in this interval.

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Walter Roberson
Walter Roberson il 14 Dic 2011
Modificato: Walter Roberson il 23 Ott 2023
You are asking to plot data that has a range of about 10^10 at one end, and about 10^20 at the other end. What are you expecting to see of interest?
T=linspace(100,1000,100);
p=89.9659+0.1110371*T-0.001472155*T.^2+ 1.1E-5*T.^3-4.381E-8*T.^4+1E-10*T.^5;
plot(T,p)

2 Commenti

mohammad
mohammad il 14 Dic 2011
Walter, do you mean Because of being so great number (10^2 to 10^20 )it's impossible to see in range of 100 to 1000?
in this interval, value of function is between 0.95 to 0.98 .
No. Because you have small coefficients, the range of p is not from 10^2 to 10^20. The maximum value of p is around 7e4.
The point is, you can specify any range of T as you want, use linspace() or 100:100:1000, then use array power ".^" not the matrix power "^" to evaluate p, and then you can use plot().

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x=-5:.1:5;
p=[1 -1 -11 9 18] % polynomial function
p = 1×5
1 -1 -11 9 18
plot(x,polyval(p,x))
grid on
%solve1
fplot(@(x)89.9659+0.1110371.*x-0.001472155.*x.^2+1.1E-5.*x.^3-4.381E-8.*x.^4+1E-10.*x.^5)

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