how can i use integral2 for a vector-valued function ?

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for example i wrote this code:
% code
f=@(x,y)x+y;
g=@(x,y)x^2+y^2;
h=@(x,y)x/y+y/x;
w=@(x,y)sin(x)+cos(y);
box=@(x,y)[f(x,y) g(x,y);h(x,y) w(x,y)];
answers=integral2(box,1,2,1,2)
i expected answers to be a 2*2 scalar matrix but i got only error... what to do?

Risposta accettata

Star Strider
Star Strider il 5 Set 2015
Modificato: Star Strider il 5 Set 2015
They’re not 'ArrayValued' in the sense integral understands, and only integral — and not integral2 — can handle array-valued arguments. Otherwise, you could just use integral twice, the second time on the result of the first.
They’re also essentially independent of each other, so integrate them individually using integral2 and then put them together in a matrix at the end.
Specifically:
% Vectorised Equations:
f = @(x,y)x+y;
g = @(x,y)x.^2+y.^2;
h = @(x,y)x./y+y./x;
w = @(x,y)sin(x)+cos(y);
intf = integral2(f,1,2,1,2);
intg = integral2(g,1,2,1,2);
inth = integral2(h,1,2,1,2);
intw = integral2(w,1,2,1,2);
answers = [intf intg; inth intw]
answers =
3.0000 4.6667
2.0794 1.0243
  5 Commenti
祥宇 崔
祥宇 崔 il 10 Apr 2023
Thanks! As you suggested, we can use 'integral' for twice only when these two variables are independent to each other. But what if we can't seperate them? For instance:
fun = @(n,x,y) sin(n*x-y).*sqrt(x-n*y);
for i=1:1e3
integral2(@(x,y) fun(i,x,y),0,2*pi,0,2*pi);
end
Is there anaway to speed it up by vectorizing it?
祥宇 崔
祥宇 崔 il 10 Apr 2023
If you got any idea, here is my question.
Thanks!
https://ww2.mathworks.cn/matlabcentral/answers/1944314-how-to-vectorize-integral2

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