Write a MATLAB program to sketch the following discrete-time signals in the time range of –10 ≤ n ≤ 10. Please label all the graph axes clearly. If the sequence is complex, plot the magnitude and angle separately. i) x(n) = u(n) – u(n – 3)
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n=-10:10;
u(1:21)=ones(1,21); %creates a unit step sequence for u(n)
%how to write a delayed version of sequence i.e for u(n-3) ?
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Risposte (4)
Aliya Patel
il 23 Nov 2018
Modificato: DGM
il 4 Nov 2023
t = (-10:1:10)'; %%Can change the interval time by replacing 1 with 0.1
step1 = t>=0; %% For u[n]
step2 = t>=3; %%For u[n-3]
x = step1-step2;
plot(t,x) %%scatter can be used instead of plot
xlabel('time');
ylabel('amplitude');
title('x(n)=u(n)-u(n-3)');
2 Commenti
Satadru Mukherjee
il 21 Mar 2020
Modificato: Satadru Mukherjee
il 21 Mar 2020
n1=-10:10;
x=(n1>=0);
n2=n1+3;
y=x;
u=min(min(n1),min(n2));
t=max(max(n1),max(n2));
r=u:1:t;
z1=[];
temp=1;
for i=1:length(r)
if(r(i)<min(n1) || r(i)>max(n1))
z1=[z1 0];
else
z1=[z1 x(temp)];
temp=temp+1;
end
end
z2=[];
temp=1;
for i=1:length(r)
if(r(i)<min(n2) || r(i)>max(n2))
z2=[z2 0];
else
z2=[z2 y(temp)];
temp=temp+1;
end
end
z=z1-z2;
subplot(3,1,1);
stem(r,z1);
xlabel('Time sample');
ylabel('Amplitude');
title('First signal');
subplot(3,1,2);
stem(r,z2);
xlabel('Time sample');
ylabel('Amplitude');
title('Second signal');
subplot(3,1,3);
stem(r,z);
xlabel('Time sample');
ylabel('Amplitude');
title('Signal after Subtraction');
3 Commenti
Walter Roberson
il 16 Mag 2020
It appends x(temp) to the end of z1. They wrote the code using that technique because people tend to learn the [] concatenation before they gain the experience to initialize an array to full size and write at a particular in the array.
Bhargav Jyoti Saikia
il 27 Mar 2021
Thank you very much. This program gave a clear idea as to how to implement these functions. Took little time to understand but after little debugging got the idea. There might be easier way or easier to understand simple method to achieve the same functionality.
Jyothi
il 24 Apr 2024 alle 17:20
Questo/a risposta è stato/a segnalato/a da DGM
import numpy as np import matplotlib.pyplot as plt
- Define the range of n n = np.arange(0, 11)
- Calculate the exponential signal signal = np.exp(-0.1 * n)
- Plot the signal plt.stem(n, signal, use_line_collection=True) plt.xlabel('n') plt.ylabel('e^(-0.1n)') plt.title('Discrete Exponential Signal e^(-0.1n)') plt.grid(True) plt.show()
1 Commento
Walter Roberson
il 24 Apr 2024 alle 21:50
This appears to be python code, but MATLAB was being asked about rather than Python.
The python code does not appear to answer the question that was asked.
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