![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/178581/image.jpeg)
How do I fade colors into each other?
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Krish Desai
il 3 Ott 2015
Commentato: Image Analyst
il 4 Ott 2015
I'm trying to get red in the top right, purple in the top left, blue in the bottom right, and green in the bottom left. However, instead of fading together the colors are staying separate of each other. What am I doing wrong?
r=256;
c=256;
d=3;
A=zeros(r,c,d);
increase=linspace (0,1,256);
decrease= linspace (1,0,256);
%Top
for i=1:256
%Top
A(1:128,i,1)=1;
A(1:128,i,3)=increase(i);
%Bottom
A(128:256,i,3)=increase(i);
A(128:256,i,2)=decrease(i);
end
imagesc(A)
I add the following into my for loop: %left
A(i,1:128,1)=decrease(i);
A(i,1:128,2)=increase(i);
%right
A(i,128:256,1)=decrease(i);
A(i,128:256,3)=increase(i);
Now I get a weird triangle thing, what am I doing wrong? I want all of them to fade into each other.
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Image Analyst
il 4 Ott 2015
Try this:
rows = 256;
oneColumn = ((rows-1) : -1 : 0)';
redChannel = uint8(repmat(oneColumn, [1, rows]));
blueChannel = uint8(toeplitz((rows-1):-1:0));
greenChannel = uint8(toeplitz(0:(rows-1)));
triangleMask = logical(triu(ones(rows, rows)));
greenChannel(triangleMask) = 0;
rgbImage = cat(3, redChannel, greenChannel, blueChannel);
imshow(rgbImage);
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/178581/image.jpeg)
2 Commenti
Image Analyst
il 4 Ott 2015
Just consider watch color plane one at a time. Then figure out where the 0's need to be and where the 255's need to be and use repmat(), toeplitz(), or the colon operator to replicate a single vector over the whole array.
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