Problem with find function

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Aftab Ahmed Khan
Aftab Ahmed Khan il 3 Nov 2015
Modificato: Stephen23 il 3 Nov 2015
Hello everyone, i am having two vectors and i want to find the index by doing so but it gives me an error. However it works fine when i do like this for numbers. Any help guys.
hbs_ort = {'North' 'North' 'South' 'South' 'East' 'West' 'West' 'East'}
cabs_ort = {'North'}
match=find(cabs_ort==hbs_ort)

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Stephen23
Stephen23 il 3 Nov 2015
Modificato: Stephen23 il 3 Nov 2015
You can use strcmp to obtain the logical index (which often faster and more convenient to use than subscript indices):
>> hbs_ort = {'North' 'North' 'South' 'South' 'East' 'West' 'West' 'East'};
>> cabs_ort = {'North'};
>> X = strcmp(hbs_ort,cabs_ort) % logical index
X =
1 1 0 0 0 0 0 0
If you really need to subscripts:
>> find(X)
ans =
1 2
EDIT: if cabs_ort contains multiple values, then use ismember instead:
>> hbs_ort = {'North' 'North' 'South' 'South' 'East' 'West' 'West' 'East'};
>> cabs_ort = {'North','South'};
>> X = ismember(hbs_ort,cabs_ort)
X =
1 1 1 1 0 0 0 0
  4 Commenti
Guillaume
Guillaume il 3 Nov 2015

Possibly, this is what you want:

hbs_ort = {'North' 'North' 'South' 'South' 'East' 'West' 'West' 'East'};
cabs_ort = {'North', 'South'};
ismember(hbs_ort, cabs_ort)
Stephen23
Stephen23 il 3 Nov 2015
Modificato: Stephen23 il 3 Nov 2015
Then use ismember instead:
>> hbs_ort = {'North' 'North' 'South' 'South' 'East' 'West' 'West' 'East'};
>> cabs_ort = {'North','South'};
>> X = ismember(hbs_ort,cabs_ort)
X =
1 1 1 1 0 0 0 0
Note that the order of the input arguments to ismember is significant: it checks if the elements of A are members of B, where A and B are the first and second inputs respectively.

Accedi per commentare.

Più risposte (1)

TastyPastry
TastyPastry il 3 Nov 2015
Modified code:
hbs_ort = {'North' 'North' 'South' 'South' 'East' 'West' 'West' 'East'};
cabs_ort = 'North';
match=strfind(hbs_ort,cabs_ort);
Returns variable match, which is a 1xn cell array containing vectors where 'North' is found in each cell of hbs_ort.

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