How to count the number of zero subcells in a cell?

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I have a cell array 12*32. each element of my cell contains 32 data. for example C{11,32}='0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ' . I want to count how many of zero array like above is there in my cell. could any one help me? thanks
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Fateme Jalali
Fateme Jalali il 18 Gen 2016
t1 and t2 are my database.In this code I want to count howmany '0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0' happens in diffrcell

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Thorsten
Thorsten il 18 Gen 2016
Modificato: Thorsten il 18 Gen 2016
If you have a cell array of matrices:
C{1,1} = ones(1,32);
C{1,2} = 2*ones(1,32);
C{2,1} = zeros(1,32);
C{2,2} = zeros(1,32);
N = nnz(cellfun(@(x) nnz(x)==0, C));
If you have a cell array of cells, an additional cell2mat is needed:
C = {{rand(5,1)}, {rand(7,1)}, {zeros(6,1)}, {rand(7,1)}, {0 1 2 3}, {-1 1}};
N = nnz(cellfun(@(x) nnz(cell2mat(x))==0, C));

Walter Roberson
Walter Roberson il 18 Gen 2016
Most of the code can be replaced.
tt2u = unique(tt2{1}, 'rows');
tt3u = unique(tt3{1}, 'rows');
number_of_similar_chunks = sum( ismember(tt2u, tt3u) );
However you should clarify how you want the counting to occur if there are duplicate entries in one of the array that match the other array.

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