Azzera filtri
Azzera filtri

what am I doing wrong here?

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Jonathan Trencheny
Jonathan Trencheny il 15 Feb 2016
Risposto: Star Strider il 15 Feb 2016
function a = problem4c (m)
m=4;
a = [1:m; 2:m; 3:m; 4:m; 5:m];
x = mean(a);
avg = mean(x);
I keep getting, in red letters:
Error using vertcat
Dimensions of matrices being concatenated are not consistent.
Error in problem4c (line 3)
a = [1:m; 2:m; 3:m; 4:m; 5:m];
Error in run (line 96)
evalin('caller', [script ';']);

Risposte (2)

Image Analyst
Image Analyst il 15 Feb 2016
The rows don't have all the same number of columns. Instead of putting the vectors into different rows with semicolons, put them into the same row with commas:
a = [1:m, 2:m, 3:m, 4:m, 5:m];
  2 Commenti
Jonathan Trencheny
Jonathan Trencheny il 15 Feb 2016
I see, and that makes sense, however what would we do if we need to keep it a matrix?
Walter Roberson
Walter Roberson il 15 Feb 2016
a = {1:m; 2:m; 3:m; 4:m; 5:m};
x = cellfun(@mean, a);

Accedi per commentare.


Star Strider
Star Strider il 15 Feb 2016
I don’t know what the problem statement is, but from what I’ve seen, one option might be:
m = 4;
v = m:-1:0;
c = cumsum(0:m);
s = sum(1:m) - c;
avg = s./v
avg =
2.5 3 3.5 4 NaN

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