How can I plus (append) string in each loop?
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Yen Hai
il 12 Mar 2016
Commentato: Image Analyst
il 13 Mar 2016
I have:
person=[1,2];
for i=1:length(person)
if (person(i))== 1
str=sprintf('Person A');
elseif (output(i))==2
str=sprintf('Person B');
elseif (output(i))==3
str=sprintf('Person C');
elseif (output(i))==4
str=sprintf(' Person D');
elseif (output(i))==5
str=sprintf('Person E');
else
str=sprintf('System can not detect!');
end
end
%How can I plus result in each loop, like this:
%str='Person A Person B'
How can I plus result in each loop, like this:
str='Person A Person B'
Thank for your help!
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Risposta accettata
Image Analyst
il 12 Mar 2016
Here's another one of many ways. Not necessarily the best, but along the lines of what you started with. (Is this homework?)
person=[1, 2];
finalString = ''; % Initialize
for i=1:length(person)
if (person(i))== 1
str=sprintf('Person A');
elseif (person(i))==2
str=sprintf('Person B');
elseif (person(i))==3
str=sprintf('Person C');
elseif (person(i))==4
str=sprintf('Person D');
elseif (person(i))==5
str=sprintf('Person E');
else
str=sprintf('System can not detect!');
end
finalString = [finalString, ' ', str]; % Append this string.
end
fprintf('The final string = %s\n', finalString);
2 Commenti
Image Analyst
il 13 Mar 2016
Sure, just ask, but remember to attach your images and explain the larger context of what you want.
Più risposte (1)
dpb
il 12 Mar 2016
Modificato: dpb
il 12 Mar 2016
I presume output is a typo intending person. But you don't need a loop nor any logical tests at all...
>> people=['A':'Z']; % define population of names from which to pick
>> persons=1:3:8; % chose some arbitrarily
>> sprintf('Person %2c ',people(person))
ans =
Person A Person D Person G
>>
BTW, if don't want the trailing blank or it's a bother, simply wrap with
strtrim(sprintf('Person %2c ',people(person)))
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