I have this error "In an assignment A(I) = B, the number of elements in B and I must be the same."
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
pranith kumar
il 29 Apr 2016
Commentato: Walter Roberson
il 30 Apr 2016
My code is like
I=zeros(1,5);
for i=1:4
[ma,I(i)]=max(areas);
end
Error: "In an assignment A(I) = B, the number of elements in B and I must be the same." [ma,I(i)]=max(areas); the second argument y in [x,y]=max(a) is a single element and I am trying to send single element only right?
0 Commenti
Risposta accettata
Walter Roberson
il 29 Apr 2016
max() of a 2D array results in a vector, not a scalar. The indices of that would not fit in the single location I(i)
You should be asking yourself why you are doing the same thing in every iteration of the loop. max(areas) is not going to change in the loop.
Why are you allocating 5 locations but only looping to 4?
2 Commenti
Walter Roberson
il 30 Apr 2016
Your area variable is becoming a 2D array at some point.
Just before that section of code, add
assert(isscalar(areas), 'areas is unexpectedly array %s', str2num(size(areas)));
Più risposte (1)
Guillaume
il 29 Apr 2016
If areas is anything but a vector or scalar, then the return values of max are not scalar. See:
areas = magic(3)
[ma, l] = max(areas)
If you want the max of the whole matrix:
[ma, l(i)] = max(areas(:));
Note that in that case l(i) is the linear index of the max location.
Vedere anche
Categorie
Scopri di più su Creating and Concatenating Matrices in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!