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how to Design PID controller for second order untable process

Asked by Harshit Gole on 10 Feb 2012
Latest activity Edited by Azzi Abdelmalek
on 16 Oct 2013
How a PID controller can be designed for a second order SISO process, of the form -a/S^2-b, where a,b>0 .

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1 Answer

Answer by Arkadiy Turevskiy on 13 Feb 2012
 Accepted Answer

Not sure if that is what you are looking for, but here is how you could do it in Control System Toolbox:
>>a=1; % change to desired value
>>b=4; % change to desired value
>>s=tf('s');
>>plant=-a/(s^2-b);
>>C=pidtune(plant,'PID'); design pid controller
>>step(feedback(C*plant,1)); plot the step response of the closed-loop system
>>pidtool(plant); % open the GUI for interactive tuning
HTH. Arkadiy

  2 Comments

sir ,
after entering the command
"C=pidtune(plant,'PID');"
it is showing an error
"??? Undefined function or method 'pidtune' for input arguments of type 'tf'."
please guide me.
pidtune is new as of R2010b
http://www.mathworks.com/help/toolbox/control/rn/bsllzup-1.html

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