Azzera filtri
Azzera filtri

always having zero results

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sukaina abbas
sukaina abbas il 2 Giu 2016
Commentato: sukaina abbas il 2 Giu 2016
Hi,
I have a problem with my code.It just two equations to find unknown two values(Y,X). From the first equation, i get Y then, when I put Y in X equation, always having a value of X which is Zero. the x2 in the equation of X is 0.001.
X=0.25*((r1.^2-r2.^2-y1.^2+2*y1* *Y*)/ *x2*);
Y has an integer value and when i put its value such as 7, i get X=-1. But when i Put Y as a letter Y, i get X=0

Risposte (1)

John D'Errico
John D'Errico il 2 Giu 2016
Modificato: John D'Errico il 2 Giu 2016
Well we cannot do anything with that equation, since it is not valid syntax. There are some spare * characters near the end. I'm not sure if that was a typo, if you did it intentionally, or what.
My guess however, is that Y is not just an integer, but it is probably an integer of form like int8, int16, etc. For example:
z = 0.001 + uint8(2)
z =
2
whos z
Name Size Bytes Class Attributes
z 1x1 1 uint8
So the result is not 2.001, but exactly 2, since the result will be uint8.
Had that integer been in double precision form, the issue would not arise.
  2 Commenti
Walter Roberson
Walter Roberson il 2 Giu 2016
I think in the original the user was possibly trying to bold some of the variables
sukaina abbas
sukaina abbas il 2 Giu 2016
Yes I bold Y and x2 any the problem is being solved by just separate the equation in two parts. Many thanks for your cooperation and help

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