Calculate Hausdorff distance in millimiter

Hi,

i have calculated the hausdorff distance, the code that computes the euclidean distance is

function[dist] = compute_dist(A, B) 
m = size(A, 1); 
n = size(B, 1); 
dim= size(A, 2); 
for k = 1:m 
    C = ones(n, 1) * A(k, :); 
    D = (C-B) .* (C-B); 
    D = sqrt(D * ones(dim,1)); 
    dist(k) = min(D); 
end

giving pixel spacing wich is 1.093x1.093 mm²

if i do

function[dist] = compute_dist(A, B) 
m = size(A, 1); 
n = size(B, 1); 
dim= size(A, 2); 
for k = 1:m 
    C = ones(n, 1) * A(k, :); 
    D = (1.0973*C-1.0973*B) .* (1.0973*C-1.0973*B); 
    D = sqrt(D * ones(dim,1)); 
    %D=D*1.0937;
    dist(k) = min(D); 
end

is it true

Thanks

[Image Analyst]

What's A and C represent? And what's their size/shape? Why are there no comments in this code???

The Hausdorf algorithm can be found here: http://cgm.cs.mcgill.ca/~godfried/teaching/cg-projects/98/normand/main.html