Azzera filtri
Azzera filtri

Efficient code - Get rid of my loop

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jlt199
jlt199 il 19 Ago 2016
Commentato: Azzi Abdelmalek il 19 Ago 2016
Hi,
I'm reading in some data from a csv file, which for some reason is being read in as strings rather than doubles. Now I need to do some math so need to convert to numbers, but my strings don't all have the same number of characters. Here's an example:
B = {'5085';'10955';'6496';'6497';'2953';'5090'};
The only way I have found to convert this is to use a loop:
for count = 1:size(B,1)
B{count} = str2num(B{count});
end
B = cell2mat(B);
But there must be a more efficient, quicker, method for achieving this conversion. Any suggestions please?

Risposta accettata

Star Strider
Star Strider il 19 Ago 2016
The cellfun function works without the loop:
B = {'5085';'10955';'6496';'6497';'2953';'5090'};
Bn = cellfun(@str2num, B)
Bn =
5085
10955
6496
6497
2953
5090
  3 Commenti
Star Strider
Star Strider il 19 Ago 2016
My pleasure.
The str2num and other functions don’t work with cell arrays, but cellfun can make most functions compatible with them.
Azzi Abdelmalek
Azzi Abdelmalek il 19 Ago 2016
The cellfun is not more efficient then the for loop

Accedi per commentare.

Più risposte (1)

Azzi Abdelmalek
Azzi Abdelmalek il 19 Ago 2016
str2double(B)

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