Syntax x = fmin('fun',x1,x2)

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work wolf
work wolf il 31 Ago 2016
Commentato: Star Strider il 1 Set 2016
Syntax
x = fmin('fun',x1,x2)
x = fmin('fun',x1,x2,options)
x = fmin('fun',x1,x2,options,P1,P2, ...)
[x,options] = fmin(...)
are not working by matlab? the message from matlab as follows as:
>> f =@(x) x.^3-2*x-5;
>> x = fmin('f', 0, 2)
Undefined function 'fmin' for input arguments of type 'char'.
Did you mean:
>> x = min('f', 0, 2)
Error using min
MIN with two matrices to compare and a working dimension is not supported.
>> x = fminbnd('f', 0, 2)
Cannot find an exact (case-sensitive) match for 'f'

Risposta accettata

Star Strider
Star Strider il 31 Ago 2016
You’re almost there.
This works:
f =@(x) x.^3-2*x-5;
x = fminbnd(f, 0, 2)
x =
816.4968e-003
  18 Commenti
work wolf
work wolf il 1 Set 2016
Relly , thank you sooooo much
Star Strider
Star Strider il 1 Set 2016
As always, my pleasure!

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Più risposte (1)

Walter Roberson
Walter Roberson il 31 Ago 2016
"Note: The fmin function was replaced by fminbnd in Release 11 (MATLAB 5.3). In Release 12 (MATLAB 6.0), fmin displays a warning message and calls fminbnd."
If you are using MATLAB 5.3 or earlier, that is important information for us to know. If you are using something that old, you would use
x = fmin('f', 0, 2)
but you would also have to have created file f.m with content
function y = f(x)
y = x.^3-2*x-5;
  2 Commenti
work wolf
work wolf il 31 Ago 2016
x = fmins('fun',x0)
x = fmins('fun',x0,options)
x = fmins('fun',x0,options,[],P1,P2, ...)
[x,options] = fmins(...)
and
z = fzero('fun',x) z = fzero('fun',x,tol)
z = fzero('fun',x,tol,trace)
z = fzero('fun',x,tol,trace,P1,P2,...)
thankx, if the fmin function was replaced by fminbnd, what were replaced fmins and fzero?
Steven Lord
Steven Lord il 31 Ago 2016
fmins -> fminsearch
fzero -> fzero

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