Plotting data with timestamps

Hi,
I have some data from a sensor and corresponding timestamps. How do I plot this data? (x axis - timestamps, y-axis - data) plot function gives empty figures. Probably because timestamps cannot be put in a linear scale. I tried semilogx - this also gives empty figures.
How do I do this?
Thanks in advance

2 Commenti

Ryan Smith
Ryan Smith il 28 Nov 2016
Can you provide the data as an attachment?
lexi11
lexi11 il 28 Nov 2016
Hi, the timestamps are in unix format. I have attached a set of them. Since in excel it shows as 1.48E+10 format, I have changed the type in excel to 'number' so that you can see the entire number. So it adds .00 in the end to each value, but originally I get in the 1.48E+10 like number representation. Thank you.

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dpb
dpb il 28 Nov 2016
Modificato: dpb il 28 Nov 2016

1 voto

Convert from whatever format the timestamps are in to a Matlab representation of dates...with R2014 up, there's the datetime class; prior to that use datenum. See <datetime> for current versions; plot is datetime -aware.

7 Commenti

datetime() offers a 'ConvertFrom', 'posixtime'. The numbers you showed in the image convert into dates today if you divide them by 1000 before doing the conversion.
lexi11
lexi11 il 28 Nov 2016
This works!!! Thank you very much, dpb and Walter.
lexi11
lexi11 il 30 Nov 2016
Hi Walter, I would also like to know why we divide by 1000? Is this a standard procedure? Thanks.
what have you guys used for the dateType argument? My data is in unix timestamp
Well, Unix timestamp is in seconds from Jan 1, 1970 but your data are too big for that; they seem to have been encoded as integer values to the millisecond resolution...
>> t=datetime(1489337264031/1000,'ConvertFrom','posixtime')
t =
datetime
12-Mar-2017 16:47:44
>> t.Format=[t.Format '.SSS']
t =
datetime
12-Mar-2017 16:47:44.031
>>
You'll notice the fractional seconds match up with the last significant digits in the original number.
In recent versions of MATLAB, you can also convert directly from ms since 1970:
>> datetime(1489337264031,'ConvertFrom','EpochTime','TicksPerSecond',1000,'Format','dd-MMM-yyyy HH:mm:ss.SSS')
ans =
datetime
12-Mar-2017 16:47:44.031
The 'Epoch' parameter defaults to 1-Jan-1970, which is convenient if you have posix timestamps.
dpb
dpb il 31 Ott 2018
Thanks for making aware of that, Peter...

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