Azzera filtri
Azzera filtri

Consecutive series of numbers

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Meriem Deli
Meriem Deli il 27 Gen 2017
Risposto: Jan il 27 Gen 2017
Hello everyone,
I need some help, assume that I have a vector Days=[1 25 26 38 100 101 102 150 151 152 153 154 180 204 365] and I have to find the sequence of consecutive numbers (Duration), for exemple (25 26) , (100 101 102),(150 151 152 153 154), I tried with a for loop but I stuck on it.
Hope my question is clear, Thanks in advance
  2 Commenti
Jan
Jan il 27 Gen 2017
Please post your code and explain, what does not work as expected. What is the wanted output?

Accedi per commentare.

Risposte (1)

Jan
Jan il 27 Gen 2017
Days = [1 25 26 38 100 101 102 150 151 152 153 154 180 204 365];
[B, N, Idx] = RunLength(diff(days));
Consecutive = (B == 1);
Start = Idx(Consecutive);
len = N(Consecutive);
Now Start and Len contain the limits of the intervals.

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