how to calculate alternating summation for pi
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
How do I write code to estimate pi up to 1 million terms (n=1million) of: pi = 4(1/1 - 1/3 + 1/5 - 1/7 +...etc)
0 Commenti
Risposte (2)
Star Strider
il 31 Gen 2017
Use MATLAB vectors:
N = 1E+6; % Number Of Terms
N = 2*fix(N/2); % Assure Even Number Of Terms
sgn = -(-1).^[1:N]; % Sign Vector
denom = 1:2:2*N; % Denominator Vector
pie = 4*sum(1./(denom.*sgn)) % Desired Result
error = pi - pie % Difference Between Our Calculation And MATLAB ‘pi’
pie =
3.14159165358978
error =
1.00000001213019e-06
2 Commenti
Star Strider
il 31 Gen 2017
I’m not certain what you mean by ‘vector equations—i.e 'v =' ’ A more detailed description or explanation would be helpful.
They are already ‘vector equations’ as I interpret it. I combined them in the ‘pie’ assignment. You can break them out as a single vector and then calculate ‘pie’ as:
v = denom.*sgn;
pie = 4*sum(1./v)
While I’m thinking about it, remember to celebrate International Pi Day (to three significant digits) on March 14 (3 14 2017).
Vedere anche
Categorie
Scopri di più su Pie Charts in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!