please provide with the color identification base paper for the following code

a=0;
b=0;
c=0;
p=0;
p1=0;

I=imread('E:\projectimages\imgs\clg.jpg')
imshow(I)

fnam=imread('E:\projectimages\imgs\clg.jpg');   
figure,imshow(fnam)
for mm = 1:size(fnam,1)

      for nn = 1:size(fnam,2)

if (fnam(mm,nn,2)) > fnam(mm,nn,1) && (fnam(mm,nn,2)) > fnam(mm,nn,3)
 fnam(mm,nn,1) = fnam(mm,nn,1);
 fnam(mm,nn,2) = fnam(mm,nn,2);
 fnam(mm,nn,3) = fnam(mm,nn,3);

        a=a+1;
  %       
  else
        fnam(mm,nn,1) = 0;
        fnam(mm,nn,2) = 0;
        fnam(mm,nn,3) = 0;  
        b=b+1;

      end
    end 
  end
  p = a / (a + b);
  p1 = p * 100;

imshow(fnam);
a = sprintf('Vegetation Pixel Count= %3d',a);
b = sprintf('Non Vegetation Pixel count= %3d',b);
c = sprintf('Percentage of area of veg is %3f %',p1);
msgbox(a);
msgbox(b);
msgbox(c);

Answer 1

[Walter Roberson]

There is no "paper" for that. The code just extracts the pixels for which the green component is greater than the red or blue, and calls those pixels "vegetation". That is not a robust way to calculate vegetation. For one thing, it leaves out all brown, but a lot of wood is brown.

[BUGATHA VARALAKSHMI]

thank you so much