How can I replace NaN elements with the nearest value in the same column?

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I am trying to replace NaN's in a vector field with the nearest value.
% I have:
M=
NaN 12
18 14
NaN NaN
NaN NaN
NaN 16
12 NaN
12 NaN
NaN 12
16 NaN
%I desire:
M=
18 12
18 14
12 16
12 16
12 16
12 12
12 12
16 12
16 12
Any information will be helpful. Thank you
  2 Commenti
AstroGuy1984
AstroGuy1984 il 25 Apr 2017
Modificato: AstroGuy1984 il 25 Apr 2017
What do you mean by "nearest"? Do you mean "next good value"? Because that's what you appear to desire. For example the second NaN in column 1 is closer to 18 than 12.
sal135
sal135 il 26 Apr 2017
I would like to have the first value of NaN to have the value of the next good value. However if the last value in the column is a NaN I would like for it to have the value of the previous good value

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Andrei Bobrov
Andrei Bobrov il 25 Apr 2017
Modificato: Andrei Bobrov il 26 Apr 2017
FIXED 2
m = flipud(M)
t = ~isnan(m);
ii = cumsum(t);
ii(ii == 0) = 1;
ii = bsxfun(@plus,[0,ii(end,1:end-1)],ii);
m1 = m(t);
out = flipud(m1(ii))
  6 Commenti
Andrei Bobrov
Andrei Bobrov il 26 Apr 2017
>> m = flipud(M);
t = ~isnan(m);
ii = cumsum(t);
ii(ii == 0) = 1;
ii = bsxfun(@plus,[0,ii(end,1:end-1)],ii);
m1 = m(t);
out = flipud(m1(ii))
out =
18 12
18 14
12 16
12 16
12 16
12 12
12 12
16 12
16 12
>>
sal135
sal135 il 26 Apr 2017
Modificato: sal135 il 27 Apr 2017
Thank you for your help! This worked out great.

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dpb
dpb il 25 Apr 2017

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