How to i find the integral/derivative of a transfer function ?

have a transfer function, how to get its integral?

Answer 1

[Sebastian Castro]

Are you using Control System Toolbox? Recall that the transfer function for a derivative is s and for an integrator is 1/s. So, for example:

>> G = tf(1,[1 5 10])
>> s = tf('s')

Then

>> G_deriv = G*s;
>> G_int = G*(1/s);

If you're using discrete, you can similarly do this with z = tf('z');

- Sebastian

[Rakshith BV]

basically , my g(s)= (s)/(s^2+3*s+2) how do i find, g'(s), ie the derivative of the above function, which is a transfer function in the s domain

[Sebastian Castro]

You multiply it by s!

[Karl Magro]

So lets say you have the following trasnfer function:

(1.417s+37.83)/(s^2+1.417s+37.83)

The first derivative of it would be: (1.417s^2+37.83s)/(s^2+1.417s+37.83)

Is that correct Sebastian?

[Dhanush D Shekar]

sebastian is talkin about taking the derivative in time domain

Answer 2

[Drew]

[Walter Roberson]

I do not understand this answer to the question about taking integrals and derivatives of transfer functions.

For one thing, the integral involves the variable t but transfer functions tradtionally use s or z . Using the variable t makes it appear as if this is an integral in the time domain, in which case it is not a transfer function.

[Walter Roberson]

syms t y(x)
eqn = diff(y,x) * int(sin(t^2), t, sqrt(x), sym(pi)/4)

eqn(x) = 

char(eqn)

ans = '-(2^(1/2)*pi^(1/2)*(fresnels((2^(1/2)*x^(1/2))/pi^(1/2)) - fresnels((2^(1/2)*pi^(1/2))/4))*diff(y(x), x))/2'