Error: Undefined function or variable 'fgetl' when fgetl() is placed inside an else statement
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Hi, I'm writing a simple script to read a .csv file. I get the error:
Undefined function or variable 'fgetl'.
Error in (filename) (line 36)
line = fgetl(fid);"
It's strange because the call to fgetl() outside the if statement works fine!
if(~exist(file_in))
FInputErrMsg = 'not located in working directory.';
Suggestion = ['Change script parameter or move the file into script'...
' working directory.'];
error('Expected input file: "%s" %s\n%s',file_in,FInputErrMsg,Suggestion);
elseif(exist(file_out))
% TODO#1
end
% Open file_in1 to count the number of sites N
fid = fopen(file_in,'r');
line = fgetl(fid);
if(fid == -1)
error('Error opening %s. Exiting.', file_in);
else
line = fget1(fid); %<---------------------- Offending Line
end
fclose(fid);
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Risposta accettata
Steven Lord
il 16 Lug 2017
Check in your original code whether you're calling fgetl with a lower-case L or calling fget1 with the number one. The code segment you posted implies the latter, the error message you posted implies the former.
2 Commenti
dpb
il 16 Lug 2017
OK, but you've still got the error test for fopen out of order as written above...
Più risposte (1)
dpb
il 16 Lug 2017
fid = fopen(file_in,'r');
line = fgetl(fid);
if(fid == -1)
error('Error opening %s. Exiting.', file_in);
...
You've got the test for successful fopen out of order; that should be before you try to use it; then the fgetl call doesn't need to be inside the if construct at all. Then, it appears your fopen did fail so you called fgetl(-1) which then looks like an array reference instead of a function call since -1 isn't a valid file handle.
fid = fopen(file_in,'r');
if(fid<0), error('Error opening %s. Exiting.', file_in); end
line = fget1(fid);
fclose(fid);
...
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