how to find parallel of resistors

Is there any easy function to calculate parallel and series of resistors when i tried its showing error Wrong number of input arguments for obsolete matrix-based syntax.

[KSSV]

What you tried show us the code...

Answer 1

[Fabio Freschi]

Maybe it's too late for the OP, but for the records, I usually use an anonymous function with multiple inputs

% ananymous parallel function
p = @(varargin)1/sum(1./[varargin{:}]);
% anonymous series funciton
s = @(varargin)sum([varargin{:}]);

% data
r1 = 100;
r2 = 200;
r3 = 300;
r4 = 400;

% call the functions with an arbitrary number of inputs
p(r1,r2)
s(r1,r2)

p(r1,r2,r3)
s(r1,r2,r3)

p(r1,r2,r3,r4)
s(r1,r2,r3,r4)

[DO-HYEON CHEON]

That helped much to me. Thank you!

Answer 2

[Andrei Bobrov]

Z_parallel = 1/sum(1./z); % here z - parallel resistors
Z_series = sum(z); % here z - series  resistors

[Chaudhary P Patel]

is it correct?

Answer 3

[Jiji George]

function R = resistors( r1, r2, r3, r4, r5 )

r1 = 100;

r2 = 200;

r3 = 300;

r4 = 400;

r5 = 500;

z = [r1 r2 r3]

R = 1/(sum((1/r1)+(1/r2)+(1/r3)))

end

Answer 4

[Nav Riar]

function R = resistors( r1, r2, r3 )

r1 = 100;

r2 = 200;

r3 = 300;

z = [r1 r2 r3]

R = 1/(sum((1/r1)+(1/r2)+(1/r3)))

end