plz help me in this question
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TUSHAR MURATKAR
il 21 Lug 2017
Commentato: TUSHAR MURATKAR
il 21 Lug 2017
imnoise(I,'gaussian',0.1*5e-6); in the above line why it is 0.1*5e-6 is written.
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John D'Errico
il 21 Lug 2017
Modificato: John D'Errico
il 21 Lug 2017
Why not just read the help for imnoise? There you will find a complete explanation of the parameters for imnoise. Instead, you want someone else to re-write the help for you here?
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Star Strider
il 21 Lug 2017
My guess would be sloppy coding. That would evaluate to 5e-7.
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Star Strider
il 21 Lug 2017
As I read it, it would be the mean, since it is the first argument after 'gaussian' (at least in R2017a).
If you are using an earlier release, you need to see the documentation for the imnoise function for your MATLAB version.
Type either of these in your Command Window:
doc imnoise
or if that does not work, type:
help imnoise
to get the documentation.
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Image Analyst
il 21 Lug 2017
Because the programmer made a mistake, in my opinion, by not being explicit. According to the help:
J = imnoise(I,'gaussian',M,V) adds Gaussian white noise of mean m and variance v to the image I. The default is zero mean noise with 0.01 variance.
so it should take 2 numbers after 'gaussian', not one like they had. Perhaps they meant:
noisyImage = imnoise(I,'gaussian',0.1, 5e-6);
where there is a comma instead of a *, but who knows. You need to ask the programmer.
If they put just one number, the number would be the mean, not the variance. The variance would take on the default value of 0.01
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