Removing components of a matrix without turning it into a vector

Hello I'm trying to remove the Inf values from my matrix Z without turning it into a vector. I have an idea of how to do it using loops, and I know Z(1,:)=[] + Z(:,4)=[] will work as I want it to but I wanted to see if there's a quicker way because it seems like this should be a trivial thing for MATLAB. Z is actually a sample matrix, the matrix I am working with is larger and within a function, so the Inf locations will always be different.

Thanks!

Z =
     Inf   Inf   Inf   Inf
       4     6    13   Inf
      10    12    19   Inf
      11    18    25   Inf
  >> Z(Z==Inf)=[]
  Z =
       4    10    11     6    12    18    13    19    25

Answer 1

[Andrei Bobrov]

ii = isinf(Z);
out = Z(~all(ii,2),~all(ii));

or

ii = ~isinf(Z);
out = reshape(Z(ii),max(sum(ii)),[]);

[Roger L]

cpaceba!

[Andrei Bobrov]

:) pozhaluysta!

Answer 2

[KSSV]

doc isinf . You can pick the values from Z which are not inf, instead of removing them.

iwant = Z(~isinf(Z))

[Roger L]

Thanks for the reply. That command still returns a vector.

[KSSV]

After removing inf obviously you will get a vector....if you want a matrix...you should replace inf with some other number of your choice.

Z(isinf(Z)) = 9999

[Roger L]

I tried that, and your suggestions still yield vectors

[KSSV]

No...when you replace inf with some number it will be a matrix.

Z = [ Inf   Inf   Inf   Inf
       4     6    13   Inf
      10    12    19   Inf
      11    18    25   Inf]
Z(isinf(Z)) = 9999
Z =

          9999        9999        9999        9999
             4           6          13        9999
            10          12          19        9999
            11          18          25        9999

[Roger L]

Right, now I need to remove 9999 and only have the leftover matrix for further calculations. my goal is to remove the rows/cols of Inf variables and reduce the size of the matrix. meaning I want to go from a 4x4 to a 3x3.

Z =
     Inf   Inf   Inf   Inf
       4     6    13   Inf
      10    12    19   Inf
      11    18    25   Inf
to
Z=
   4    6    13
   10   12   19
   11   18   25

[KSSV]

Z = [ Inf   Inf   Inf   Inf
       4     6    13   Inf
      10    12    19   Inf
      11    18    25   Inf]

%%Remove _inf_ along rows
Z(any(isinf(Z(:,1))),:) =[] ;
%%Remove _inf_ along cols
Z = Z(:,~all(isinf(Z)));