Sorry, the question is: why is my underfunction not remembering my earlier value of A1 and how can i make it to remember?
loop with easy underfunction
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function tretti
for k=1:3
F=results(k)
end
function h=results(k)
A ={k*2};
A1(k)= A
h=A1
%output: F=[] [] [6]
%what i want: F=[2] [4] [6] //cell array
Risposte (1)
Rik
il 7 Nov 2017
Because you are overwriting it every iteration.
function F=tretti
for k=1:3
F{k}=results(k);
end
function h=results(k)
A ={k*2};
A1(k)= A;
h=A1;
You should look into cellfun, it may be really useful for what you are trying to do.
2 Commenti
Rik
il 7 Nov 2017
The modification of your code should work. You could also generate it as a vector or matrix, and then convert it to a cell with num2cell (or mat2cell).
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