How to find position of a time vector in another time vector?

Hi

I have two time vectors, one has random time spacing like A=[' 01/01/2001', '05/01/2001, ....], the other time vector has daily time like B=[' 01/01/2001', '01/02/2001', ....]. I like to find a position of each element of A in vector B. What is the fastest way? I don't want to write a loop for find each element. is there a faster way to output a position vector directly? Thanks a lot. I appreciate your help.

[Jan]

What exactly is a "time vector"?

A=[' 01/01/2001', '05/01/2001]

is the same as:

A = ' 01/01/200105/01/2001'

So it is not clear, what your inputs are. Does the leading space have a meaning? Is it a cell string or a datetime object?

Answer 1

[Jan]

While I'm not sure what your inputs are, most likely this will solve the problem:

[ex, loc] = ismember(A, B)

[roudan]

Thanks Jan. That works perfectly. I also found solution like this which has same result. idxs =arrayfun(@(x)find(B==x,1),A)

[Jan]

I assume the arrayfun method is much slower.