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can you please explain the working of following syntax?

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Siddhesh Karbhari
Siddhesh Karbhari il 14 Gen 2018
Chiuso: MATLAB Answer Bot il 20 Ago 2021
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
it is continuously giving 'Bad cell reference operation.' error.
extrema=zeros(1,4*number);
idx= extrema==0;
extrema(idx)=[];
extr_volume=length(extrema)/4;
for i=1:extr_volume
x=floor((extrema(4*(i-1)+3)-1)/(n/(2^(extrema(4*(i-1)+1)-2))))+1;
y=mod((extrema(4*(i-1)+3)-1),m/(2^(extrema(4*(i-1)+1)-2)))+1;
rx=x+1;
ry=y+1;
rz=extrema(4*(i-1)+2);
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
size(z)
if(abs(z)<threshold)
extrema(4*(i-1)+4)=0;
end
end

Risposte (1)

Star Strider
Star Strider il 14 Gen 2018
The code you posted does not make sense. It sets ‘extrema’ to an empty array, so all references to elements of ‘extrema’ would throw errors, because they do not exist.
  3 Commenti
Star Strider
Star Strider il 14 Gen 2018
I cannot run the code that you attached.
I will delete my Answer in a few hours.
Walter Roberson
Walter Roberson il 14 Gen 2018
We do not have your b.jpg to test with. I copied the demo image car2.jpg to b.jpg and ran the code without difficulty.
"Bad cell reference operation" is not a MATLAB error message. Is it possible that you were running under Octave?

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