Dividing a set of numbers into set of intervals and caculating the mean of each interval and comparing it with the previous one
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Mohamed Saleh
il 7 Feb 2018
Commentato: Mohamed Saleh
il 11 Feb 2018
Hi. I have a set of random numbers let's say x=[-2,-4,-7,-1,...,-3], and I need writting a code to divide x into equal intervals (let's say each interval has 50 numbers), then I want to caculate the mean of each interval and compare it with the mean of the previouse interval. Can any one help me with that please. your help is much appreciated in advanced.
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Jos (10584)
il 8 Feb 2018
Modificato: Jos (10584)
il 8 Feb 2018
I understood your question somewhat different: "I have N numbers {x(1) x(2) ... x(N-1) x(N)} and want to split them into several groups of K values: {x(1) ... x(K)} { x(K+1) ... x(2*K)} {...} without not changing the order of the elements. For each group I would like to take the mean."
There are several ways to answer this question. Examples:
% some data
X = randi(10,1,10) % N = 10
K = 3
% Note that N is not necessarily a multiple of K
idx = 1 + floor((0:numel(X)-1)/K)
M1 = accumarray(idx(:), X(:), [], @mean)
M2 = arrayfun(@(ix) mean(X(ix:min(ix+K-1,end))), 1:K:numel(X))
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