Azzera filtri
Azzera filtri

Coloring curves wrt to a third variable and creating legend for the same

1 visualizzazione (ultimi 30 giorni)
Hello, I need to plot 31 curves and their color needs to be according to a third variable that varies from 1 to 5. I tried writing the code as follows:
colorspec1 = colormap(jet(5));
for i = 1:31
for j = 1:5
if MA(i,2) == j
semilogx(All_112(:,1), All_112(:,i+1),'-', 'Linewidth', 2, 'Color', colorspec1(j,:));
hold all
end
legendInfo{j} = ['Wind Speed = ' num2str(j)];
end
end
legend(legendInfo);
I am getting curves with varying colors, but something is wrong with the code as when I change the loop positions and define j before i, the color of some curves also changes, which should not happen. I am unable to fix this issue and would need your help. Another issue is that I need a legend with 5 different colored lines in the colormap to define the third variable, but unable to get that with this version of the code. Could you please give me some direction how to do that? Thanks.
  6 Commenti
Hems
Hems il 10 Feb 2018
No worries. Thank you very much for your help. It works with plot.
Greg
Greg il 13 Feb 2018
My updated answer should better solve the down-selected legend. There's a chance it isn't compatible with your release of MATLAB; I'm not sure when the behavior of legend I'm taking advantage of was added.

Accedi per commentare.

Risposta accettata

Greg
Greg il 10 Feb 2018
Modificato: Greg il 13 Feb 2018
There's no reason to loop over colors - you already have the index in MA(i,2). Assuming the second column of MA is restricted to 1:5, use this:
colorspec1 = colormap(jet(5));
hline = gobjects(31,1);
for ii = 1:31
icolor = MA(ii,2);
hline(ij) = semilogx(All_112(:,1),All_112(:,ii+1),'-', ...
'Linewidth',2,'Color',colorspec1(icolor,:), ...
'DisplayName',sprintf('Wind speed = %d',icolor));
hold all
end
[~,inds] = unique(MA(:,2));
legend(hline(inds));
  6 Commenti

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by