Azzera filtri
Azzera filtri

how to delete this error?

3 visualizzazioni (ultimi 30 giorni)
zero
zero il 14 Feb 2018
Risposto: Image Analyst il 15 Feb 2018
function y = dd(x)
% x is a vector
% We create an output vector of only 0 (our default value)
y = zeros(1, length(x));
% We find indexes of input values equal to 0,
% and make them 1
y(find(x==0)) = 1;
function y = dd(x)
Error: Function definitions are not permitted in this context.

Risposte (3)

Jos (10584)
Jos (10584) il 14 Feb 2018
or even shorter
y = ~x

Jan
Jan il 14 Feb 2018
Modificato: Jan il 14 Feb 2018
Error: Function definitions are not permitted in this context.
This means, that you either try to create this function in the command window, or inside a script while using Matlab < R2016b.
Function can be defined in the editor inside an "M-function-file" (an M-file which starts with the keyword "function"), or with using a modern Matlab version in a "M-script-file" (an M-file not starting with "function").
By the way: As Birdman has mentioned already, the find() can be omitted:
y = zeros(1, length(x));
y(x==0) = 1;
Or even shorter:
y = (x == 0);

Image Analyst
Image Analyst il 15 Feb 2018
You are defining a function dd(x), but then at line 9 of that function you try to define a nested function with the very same name, dd(), nested inside the dd() function. That is, if you're ending your functions with the "end" keyword.
function y = dd(x)
% x is a vector
% We create an output vector of only 0 (our default value)
y = zeros(1, length(x));
% We find indexes of input values equal to 0,
% and make them 1
y(find(x==0)) = 1;
function y = dd(x)
Error: Function definitions are not permitted in this context.
Why??? You can't do that. You already have a dd function, why would you want another one of the same name to be defined inside of it???
Or, if you're defining functions without the "end" keyword, then you're not nesting but you're defining two functions with the same name in the same m-file. Again, Why???? You can't do that.

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