if inside of for loop
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I don't know what is wrong with this code. The code works when I don't include the if statement. Any idea?
for i = 1:3
if rt > 100 & rt < 1000
average(i) = mean(rt(cue==i))
dev(i) = std(rt(cue==i))
end
end
1 Commento
the cyclist
il 19 Feb 2018
You are leaving too much for us to guess at, which makes it difficult for us to help you.
Please describe what you mean by "doesn't work" in more detail. Does the code give an error? If so, tell us the complete error message, and which line it occurs on.
If it does not give an error, but just an unexpected result, tell us the expected and actual result.
In general, it would be better to supply code that we can actually run ourselves (e.g. by supplying the values of rt and cue.)
Risposta accettata
Jan
il 19 Feb 2018
Modificato: Jan
il 20 Feb 2018
Or perhaps:
match = (rt > 100 & rt < 1000);
rtx = rt(match);
cuex = cue(match);
for i = 1:3
average(i) = mean(rtx(cuex==i))
dev(i) = std(rtx(cuex==i))
end
Note that "if rt > 100 & rt < 1000" is evaluated as:
if all(rt > 100 & rt < 1000) && ~isempty(rt)
2 Commenti
Alejandro Estudillo
il 20 Feb 2018
Modificato: Alejandro Estudillo
il 20 Feb 2018
Jan
il 20 Feb 2018
@Alejandro: Yes, this way a typo. Inside the loop rtx and cuex are needed. I've fixed this in my answer.
Più risposte (1)
Birdman
il 19 Feb 2018
Modificato: Birdman
il 19 Feb 2018
You probably forgot subscripting of rt.
for i = 1:3
if rt(i) > 100 & rt(i) < 1000
average(i) = mean(rt(cue==i))
dev(i) = std(rt(cue==i))
end
end
2 Commenti
Birdman
il 20 Feb 2018
But again
rt(cue==i)
this will result in an array. You may perhaps do it before the loop and give it subscripted to for loop as
rt=rt(cue==i);
for i=1:3
if rt(i)...
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