Error: GA function - Too many output arguments

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Hello, I am trying to use the ga function to obtain the PID controller gains to a step response in order to minimize the IAE (integral of the absolute error) and I am running the code below.The problem is that when I try to use the Optimization Tool, I always get the 'Too many output arguments' error message.
function myFitness(k)
syms s
SP = 1;
G = (2.156/(42.56*s + 1))*exp(-1.005*s)
C = (k(1) + (k(2)/s) + k(3)*s);
H = feedback(G*C,1);
[z,t] = step(SP*H);
error = abs(SP-z(end));
y = integral(error,0,1000)
end
  2 Commenti
Stephen23
Stephen23 il 4 Mar 2018
@pbarros: how are you calling this fitness function? Please show the complete error message and the code where this error actually occurs.
pbarros
pbarros il 4 Mar 2018
Hi, I created the function so I could use it to obtain the controller gains using the Optimization Tool in which I set the Fitness function to '@myFitness' and the number of variables to '3'. The complete error message that I get from the Optimization Tool when I try to run the solver is the following: ' Optimization running. Error running optimization. Too many output arguments.'
In the command window there is the warning below but I did what it asked and nothing changed.
Warning: You are using 'mutationuniform' mutation function for constrained minimization.
Solution may be infeasible; use '@mutationadaptfeasible' function for constrained minimization.
> In constrValidate (line 76)
In gacommon (line 125)
In ga (line 336)
In callSolver (line 32)
In optimguirun (line 40)
In optimguiswitchyard (line 14)

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Star Strider
Star Strider il 4 Mar 2018
There are several problems with your code, not the least of which is your invoking the Symbolic Math Toolbox that is inappropriate here.
See the documentation for the tf (link) function.
This should run. I leave it to you to determine that it produces the correct result:
function myFitness(k)
s = tf('s');
SP = 1;
G = (2.156/(42.56*s + 1))*exp(-1.005*s)
C = (k(1) + (k(2)/s) + k(3)*s);
H = feedback(G*C,1);
[z,t] = step(SP*H);
err_fcn = @(z) abs(SP-z(end));
y = integral(err_fcn,0,1000, 'ArrayValued',1)
end
  8 Commenti
pbarros
pbarros il 4 Mar 2018
I am trying to get the best gains values ('k') that minimizes the error function (between the reference signal ('SP') and the step response 'z' function). I must have made a mistake somewhere because I think I should get a very small value for the 'fval'. Thank you for the help and I am sorry for all the confusion.
Star Strider
Star Strider il 4 Mar 2018
As always, my pleasure.
No worries!
A classical control approach may not be the best option here.

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