Azzera filtri
Azzera filtri

how to get odd rows and columns,even rows and columns

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A1 is the lena image
A is to the first row
similarly how to get the even rows ,even columns,odd rows,odd columns
A1 = imread('lena1.jpg');
A=A1(:,1);
  3 Commenti
juveria fatima
juveria fatima il 14 Mar 2018
i want to store all the rows one by one
i am finding the probability of each row one by one similarly each column one by one
(sum of probabilities should be one)
here is my code
%A = randi(255, [1 10]);
% A = imread('lena1.jpg');
A1 = imread('lena1.jpg');
A=A1(:,1);
A = reshape(uint8(A), [1 512*1]);
s = size(A);
[rows columns numberOfColorBands] = size(A);
col1 = 1;
col2 = floor(columns/2);
col3 = col2 + 1;
row1 = 1;
row2 = floor(rows/2);
row3 = row2 + 1;
% Now crop
upperLeft = imcrop(A, [col1 row1 col2 row2])
count = zeros(1,256);
for i =1:s(1)
for j =1:s(2)
count(uint8(A(i,j)+1)) = count(uint8(A(i,j)+1))+1;
end
end
count = double(count) /(512*1);
sumofprob=sum((count))
plot(count)

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Birdman
Birdman il 13 Mar 2018
Consider you have number of rows and columns which is an even number,
Odd rows:
A1(1:2:end-1,:)
Even rows:
A1(2:2:end,:)
Odd columns:
A1(:,1:2:end-1)
Even columns:
A1(:,2:2:end)
  3 Commenti
Jos (10584)
Jos (10584) il 14 Mar 2018
By substracting one, you discard the last odd row (column) when the number of rows (columns) of the array is odd. When this number is even, it does not matter, so just to be flexible, do not subtract one :)
Birdman
Birdman il 14 Mar 2018
Yes you are right Jos, therefore at the beginning of the question, I stated that:
Consider you have number of rows and columns which is an even number
:)

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