Define bar3() colors with hold on

I am trying to control the colors in a bar3() plot using hold on, but I keep over-riding my previous plot.
My code is below. Goal image is shown as 1st JPEG, and current Matlab plot is second JPEG. Data are also uploaded as text file.
fid001 = fopen('T001_RP2_Deagg_Combined_mod.txt', 'r');
header = textscan(fid001, '%s %s %s %s %s %s', 1 , 'HeaderLines', 0);
data = textscan(fid001, '%f %f %f %f %f %f', 'Delimiter', '\t');
fclose(fid001);
data = cell2mat(data);
Bin1_BeginRow = 1;
Bin1_EndRow = max(data(:,1)) * max(data(:,5));
Bin2_BeginRow = Bin1_EndRow + 1;
Bin2_EndRow = Bin2_BeginRow + Bin1_EndRow - 1;
Bin3_BeginRow = Bin2_EndRow + 1;
Bin3_EndRow = Bin3_BeginRow + Bin1_EndRow - 1;
Bin4_BeginRow = Bin3_EndRow + 1;
Bin4_EndRow = Bin4_BeginRow + Bin1_EndRow - 1;
Bin5_BeginRow = Bin4_EndRow + 1;
Bin5_EndRow = Bin5_BeginRow + Bin1_EndRow - 1;
Bin6_BeginRow = Bin5_EndRow + 1;
Bin6_EndRow = Bin6_BeginRow + Bin1_EndRow - 1;
%%%%%%%%%%Bin1
data1 = data(Bin1_BeginRow:Bin1_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
bar3(data2)
b = bar3(data2);
set(b,'FaceColor',[1 0 1]); % magenta
hold on
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin2
data1 = data(Bin2_BeginRow:Bin2_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[0 0 1]); % blue
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin3
data1 = data(Bin3_BeginRow:Bin3_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[0 1 0]); % green
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin4
data1 = data(Bin4_BeginRow:Bin4_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[1 1 0]); % yellow
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin5
data1 = data(Bin5_BeginRow:Bin5_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[0 1 1]); % cyan change to orange
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin6
data1 = data(Bin6_BeginRow:Bin6_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[1 0 0]); % red
clear data1 data2 i xx yy zz
XBins = {'5.0 - 5.5'; '5.5 - 6.0'; '6.0 - 6.5'; '6.5 - 7.0'; '7.0 - 7.5'; '7.5 - 8.0'; '8.0 - 8.5'; '8.5 - 9.0'};
set(gca,'xtick',[1:8],'xticklabel',XBins)
YBins = {'0 - 5'; '5 - 10'; '10 - 15'; '15 - 20'; '20 - 25'; '25 - 30'; '30 - 40'; '40 - 50'; '50 - 75'; '75 - 100'; '100 - 200'};
set(gca,'ytick',[1:11],'yticklabel',YBins)
xtickangle(290)
ytickangle(30)
hold off;

 Risposta accettata

It is necessary to reverse the order:
%%%%%%%%%%Bin1
data1 = data(Bin6_BeginRow:Bin6_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
bar3(data2)
b = bar3(data2);
set(b,'FaceColor',[1 0 1]); % magenta
hold on
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin2
data1 = data(Bin5_BeginRow:Bin5_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[0 0 1]); % blue
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin3
data1 = data(Bin4_BeginRow:Bin4_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[0 1 0]); % green
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin4
data1 = data(Bin3_BeginRow:Bin3_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[1 1 0]); % yellow
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin5
data1 = data(Bin2_BeginRow:Bin2_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[0 1 1]); % cyan change to orange
clear data1 data2 i xx yy zz
%%%%%%%%%%Bin6
data1 = data(Bin1_BeginRow:Bin1_EndRow, :);
data2 = zeros(max(data1(:, 1)), max(data1(:, 5)));
for i = 1:length(data1)
xx = data1(i, 1);
yy = data1(i, 5);
zz = data1(i, 4);
if zz > data2(xx, yy)
data2(xx, yy) = zz;
end
end
b = bar3(data2);
set(b,'FaceColor',[1 0 0]); % red
clear data1 data2 i xx yy zz
XBins = {'5.0 - 5.5'; '5.5 - 6.0'; '6.0 - 6.5'; '6.5 - 7.0'; '7.0 - 7.5'; '7.5 - 8.0'; '8.0 - 8.5'; '8.5 - 9.0'};
set(gca,'xtick',[1:8],'xticklabel',XBins)
YBins = {'0 - 5'; '5 - 10'; '10 - 15'; '15 - 20'; '20 - 25'; '25 - 30'; '30 - 40'; '40 - 50'; '50 - 75'; '75 - 100'; '100 - 200'};
set(gca,'ytick',[1:11],'yticklabel',YBins)
xtickangle(290)
ytickangle(30)
hold off
This should do what you want.

4 Commenti

That is perfect, thank you!
A follow-on query...is there a way to set the colors outside of the RGB list? I tried something like this:
bar3(data2)
b = bar3(data2);
set(b,'FaceColor',[226 60 88]); % reddish
hold on
but it threw an error
As always, my pleasure!
You can define whatever colors work. The only constraint that I know of is that they must be RGB triplets, with the elements defined on [0,1]. To use the color vector you posted, you have to normalise it.
One possibility:
[226 60 88]/max([226 60 88])
That works — I tested it. Experiment to get the result you want.
newbie9
newbie9 il 26 Mar 2018
Perfect!! Many thanks!
Thank you! Again, my pleasure!
Yours was an interesting problem!

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