Please help me convert equation to matlab code.

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adi putra
adi putra il 1 Apr 2018
Commentato: Walter Roberson il 18 Ago 2022
Questo/a domanda è stato/a segnalato/a da 2 collaboratori
Deal all.
I need you help to convert this equation to matlab code
I spend a lot of time to write it but it doesn't work. Thank you.
  1 Commento
Walter Roberson
Walter Roberson il 1 Apr 2018
Are you permitted to use the symbolic toolbox?
Is the question about providing some kind of symbolic proof, or is it about calculation of the formula using finite precision and a particular numeric input?

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Risposte (8)

Birdman il 1 Apr 2018
Modificato: Birdman il 1 Apr 2018
Basically, Symbolic Toolbox will help you:
syms y(x) n
  4 Commenti
Roger Stafford
Roger Stafford il 1 Apr 2018
@Birdman: I think you meant f(pi/2)
Birdman il 1 Apr 2018
Yes, I just now edited it Roger.

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Roger Stafford
Roger Stafford il 1 Apr 2018
N = 100; % <-- Choose some large number
s = x;
for n = 2*N-1:-2:1
s = x - s*x^2/((n+2)*(n+1));
(I think you meant to take the limit as N approaches infinity, not x.)

kalai selvi
kalai selvi il 15 Set 2020
pls answer this question to write the equation into code
  2 Commenti
John D'Errico
John D'Errico il 15 Set 2020
Please don't post a completely distinct question as an answer.
Walter Roberson
Walter Roberson il 15 Set 2020
π is written as pi in MATLAB.
exp of an expression is written as exp(expression) in MATLAB.
is written as sqrt(expression) in MATLAB.

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kalai selvi
kalai selvi il 16 Set 2020
How to write a code on IOTA filter in fbmc system

Kunwar Pal Singh
Kunwar Pal Singh il 26 Apr 2021
please answer to write this equation into MATLAB CODE
  1 Commento
Walter Roberson
Walter Roberson il 26 Apr 2021
%these variables must be defined in a way appropriate for your situation
S_N = rand() * 10
theta = randn() * 2 * pi
l = randi([2 10])
b_1 = rand()
c_11 = rand()
t_year = randi([1950 2049])
d_11 = rand()
t_1 = rand()
t_x = t_1 + rand()
lambda_a = randi([500 579])
LOTF_a = rand()
P = rand()
K_l = rand()
k_0 = rand()
t_tau = randi(10)
overhaulcost_a = 1000 + rand()*100
%the work
syms t
part1 = int(S_N .* cos(theta) .* l .* b_1 .* t_year .* d_11, t, t_1, t_x);
part2 = int(lambda_a .* LOTF_a, t, t_1, t_x);
part3 = int(P*K_l .* t_year + P .* k_0 .* l .* l .* t_tau, t, t_1, t_x);
part4 = overhaulcost_a ;
result = part1 - part2 - part3 - part4;

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Jakub Laznovsky
Jakub Laznovsky il 19 Mag 2021
Hi guys, can you please help me with conversion this piece of code to the mathematical equation?
It i a simple 3D mask proceeding the image, and searching for adjoining number one and number two. Thank you in advance.
m1=[0 0 0; 0 1 0; 0 0 0];
m2=[0 1 0; 1 1 1; 0 1 0];
for i=2:size(image,1)-1
for j=2:size(image,2)-1
for k=2:size(image,3)-1
if sum(unique(help_var(mask==1)))==3
new_image(i,j,k)=3; %marks adjoining pixel with number 3
  4 Commenti

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Adhin Abhi
Adhin Abhi il 4 Gen 2022
(λlog vmax−log vmin) /(vmax−vmin )

Lukasz Sarnacki
Lukasz Sarnacki il 17 Ago 2022
Please help
  5 Commenti
Lukasz Sarnacki
Lukasz Sarnacki il 17 Ago 2022
Thay all are arrays
A(x; y) is the average intensity of the fringe image
B(x; y) is the so-called intensity modulation.
ϕ is the corresponding wrapped phase
Walter Roberson
Walter Roberson il 18 Ago 2022
syms n N integer
syms A(x,y) B(x,y) phi(x,y)
Pi = sym(pi)
Pi = 
I(n,x,y) = A(x, y) + B(x,y) * cos(phi(x,y) - 2*Pi*n/N)
I(n, x, y) = 
numerator = simplify(symsum(I(n, x, y) .* sin(2*Pi*n/N), n, 0, N-1))
numerator = 
denominator = simplify(symsum(I(n, x, y) .* cos(2*Pi*n/N), n, 0, N-1))
denominator = 
eqn = phi(x,y) == atan(numerator ./ denominator)
eqn = 
ans = 

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