Could anyone help me to solve the following issue.

I want to calculate the throughput using the following expression

for v =1:size(B,2)
  for u =1:size(A,1)
    throughput(u,v) =(Bmax.*log2(1+(((A(u,v)).*(B(u,v))/(noise+sum(B(1:u-1,v)).*A(u,v))))))
  end
  end

where

Bmax=3000;
noise=10;

and A and B gets generated by the code and the result for A and B was

A=[0         0         0         0    0.0447         0
   0         0         0         0    0.0294         0]
B=[0         0         0         0    0.2428         0
   0         0         0         0    0.4424         0]
A=[0         0    1.9728         0         0         0
   0         0    0.0000         0         0         0]
B=[0         0    0.1971         0         0         0
   0         0    0.2703         0         0         0]
A=[0.2373    0.2169         0    0.1979         0    0.2098
   0.0174    0.0186         0    0.0214         0    0.0249]
B=[0.2160    0.7904         0    0.4386         0    0.8620
   0.3774    0.9493         0    0.8335         0    0.9899]

When the code executes the throughput was calculated with respect to last array of A and B.

But i want to calculate the throughput with respect to all arrays of A and B one by one using the for loop throughput expression.Could anyone help me to fix the issue.

[KSSV]

Similar question is answered.......follow the same here too.

[Prabha Kumaresan]

I tried but i am getting the error as the code executes
Bmax=3000;
noise=10;
A=[0         0         0         0    0.0447         0
   0         0         0         0    0.0294         0]
B=[0         0         0         0    0.2428         0
   0         0         0         0    0.4424         0]
A=[0         0    1.9728         0         0         0
   0         0    0.0000         0         0         0]
B=[0         0    0.1971         0         0         0
   0         0    0.2703         0         0         0]
A=[0.2373    0.2169         0    0.1979         0    0.2098
   0.0174    0.0186         0    0.0214         0    0.0249]
B=[0.2160    0.7904         0    0.4386         0    0.8620
   0.3774    0.9493         0    0.8335         0    0.9899]
N = length(A) ;
throughput = cell(N,1) ;
for k =1:N
for v =1:size(B,2)
for u =1:size(A,1)
    throughput(u,v) =(Bmax.*log2(1+(((A(u,v)).*(B(u,v))/(noise+sum(B(1:u-1,v)).*A(u,v))))))
end
end
end

with respect to the code i cannot mention A{1},B{1},A{2},B{2},C{3},C{3} as A and B array are generated by the code.could you please help me to solve it.

Answer 1

[Walter Roberson]

Use the same technique I showed you in https://www.mathworks.com/matlabcentral/answers/393815-could-anyone-tell-me-how-to-store-the-result-of-each-iteration-in-an-array-for-the-following-code#answer_314290 and https://www.mathworks.com/matlabcentral/answers/393813-could-anyone-tell-me-how-to-get-the-iterations-with-different-values-in-the-code-where-rng-is-used#answer_314286

"Store everything you might need later. You can always go back afterwards and clean up the parts you did not turn out to need.

Rule of programming: get it to work first, optimize afterwards."