Matrix indexing - Picking columns

1 visualizzazione (ultimi 30 giorni)
bondpen
bondpen il 15 Apr 2018
Commentato: Jan il 16 Apr 2018
So I trying to give an output a matrix which contains every fifth column of input (A). Below is what my current script look like.
function B = Script30( A )
B = A(:,1:5:end);
end
  5 Commenti
bondpen
bondpen il 15 Apr 2018
Modificato: bondpen il 15 Apr 2018
I just in habit in this naming scheme lmao.
It giving me rows instead of columns.
Jan
Jan il 16 Apr 2018
What give you rows? The shown code extracts columns.

Accedi per commentare.

Risposta accettata

David Fletcher
David Fletcher il 15 Apr 2018
Do you mean this instead of your 1:5:end?
5:5:end
If you explicitly also want column 1 the you could use [1 5:5:end]
  12 Commenti
bondpen
bondpen il 15 Apr 2018
Yea, that does the trick. What is ":," for? Does it tell command to choose columns?
David Fletcher
David Fletcher il 15 Apr 2018
What the first colon? It means all rows and columns 5,10,15...etc. If you don't have the first colon - as you have found - it will compact all selected columns into one row. Well that was a bit harder than it should have been, I think I need a lie down.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Creating and Concatenating Matrices in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by