Transfer a matrix in a quick way

2 visualizzazioni (ultimi 30 giorni)
yu xu
yu xu il 30 Mag 2012
a matrix' size is 4*300 i want to transfor it to 400*3
the method is
FROM
a a a b b b c c c ……(300 column)
a a a b b b c c c ……(300 column)
a a a b b b c c c ……(300 column )
a a a b b b c c c ……(300column )
TO
a a a
a a a
a a a
a a a
b b b
b b b
b b b
b b b
c c c
c c c
c c c
c c c
…… 400 ROW
it just changes some data's position . i need a quick way to do it , Thanks!!! --
  1 Commento
Andrei Bobrov
Andrei Bobrov il 30 Mag 2012
a = kron(1:3,ones(4,3))
out = reshape(permute(reshape(a,size(a,1),3,[]),[1 3 2]),[],3)

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Risposta accettata

Geoff
Geoff il 30 Mag 2012
If you want to preserve each 4x3 block, you could try something like this:
B = reshape(A(:, [1:3:end, 2:3:end, 3:3:end]), [], 3 );
  1 Commento
yu xu
yu xu il 30 Mag 2012
thank you very much.

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Più risposte (1)

Thomas
Thomas il 30 Mag 2012
You can use reshape
doc reshape
Eg.
a={'a' 'a' 'a' 'b' 'b' 'b' 'c' 'c' 'c';'a' 'a' 'a' 'b' 'b' 'b' 'c' 'c' 'c';
'a' 'a' 'a' 'b' 'b' 'b' 'c' 'c' 'c';'a' 'a' 'a' 'b' 'b' 'b' 'c' 'c' 'c'}
out=reshape(a,3,[])'
out=
'a' 'a' 'a'
'a' 'a' 'a'
'a' 'a' 'a'
'a' 'a' 'a'
'b' 'b' 'b'
'b' 'b' 'b'
'b' 'b' 'b'
'b' 'b' 'b'
'c' 'c' 'c'
'c' 'c' 'c'
'c' 'c' 'c'
'c' 'c' 'c'
  2 Commenti
Thomas
Thomas il 30 Mag 2012
true, in this case im assuming a=a :)

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