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Extracting every n number of column from matrix matlab

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0 down vote favorite I need to extract every n number of column from my matrix. Please note that not every nth column. For example I have a matrix:
A =
1 23 34 53 67 45 67 45
12 34 45 56 67 87 98 12
1 2 3 45 56 76 87 56
And I want to extract each 3 column, so my data should be like:
X =
1 23 34 67 45 67
12 34 45 67 87 98
1 2 3 56 76 87
So I would skip 4th column then 8th column and so on. I know how to extract every nth column and row but I couldn't figure it out what I need. Appreciated for your help

Risposta accettata

Ameer Hamza
Ameer Hamza il 3 Mag 2018
Modificato: Ameer Hamza il 3 Mag 2018
Here is a general solution to your problem in which you can specify how many columns to keep and how many to delete
colToKeep = 2;
colToDelete = 3;
ColIndex = mod( 0:size(A,2)-1, colToKeep+colToDelete ) < colToKeep;
A(:, ~ColIndex) = [];
Use colToKeep and colToDelete to specify the values.
  6 Commenti
Ameer Hamza
Ameer Hamza il 16 Ago 2018
Just take the transpose of the matrix and apply the same method. At the end take the transpose again to get the correct matrix.

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Più risposte (2)

Yuvaraj Venkataswamy
Yuvaraj Venkataswamy il 3 Mag 2018
Modificato: Yuvaraj Venkataswamy il 3 Mag 2018
Answer is below where A is a your matrix.
if true
n=4;
A =[1 23 34 53 67 45 67 45
12 34 45 56 67 87 98 12
1 2 3 45 56 76 87 56]
A(:,n:n:end) =[]
end
  1 Commento
Aybars
Aybars il 3 Mag 2018
Hi, Thank you very much for your answer. It is correct. But in that case, how can I adjust the number of column that I want to skip ? For example I would like to take first 2 columns, then skip 3 columns then take 2 columns again.

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Guillaume
Guillaume il 3 Mag 2018
X = A;
X(:, 4:4:end) = [];
  1 Commento
Aybars
Aybars il 3 Mag 2018
Hi, Thank you very much for your answer. It is correct. But in that case, how can I adjust the number of column that I want to skip ? For example I would like to take first 2 columns, then skip 3 columns then take 2 columns again.

Accedi per commentare.

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