how i can find the Entropy for 3 probabilities by matlab?
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Tammun filistin
il 27 Mag 2018
Commentato: Ankita Bansal
il 4 Giu 2018
Hello Every one
Im trying to calculate the entropy for three random values as shown in the following script , but it gives me an error . could any one please help me to find the correct answer. Many thanks.
if true
p00=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p01=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p02=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
for i=1:length(p00)
for j=1:length(p01)
for k=1:length(p02)
p03=1-p00(1,i)-p01(1,j)-p02(1,k)
H(i,j,k) = real((-p00(1,i).*log2(p00(1,i))-(p01(1,j)).*log2(p01(1,j))-p02(i,j,k).*log2((p02(i,j,k)))-p03(i,j,k).*log2((p03(i,j,k)))))
end
end
end
end
0 Commenti
Risposta accettata
Ankita Bansal
il 28 Mag 2018
Hi, first thing which is incorrect in your code is that you are trying to access p02(1,1,2) however p02 is 1x7 matrix. Similarly check for other syntaxes also. Second, I am not getting what are p00, p01 and p02. What is meaning of a vector here?
2 Commenti
Ankita Bansal
il 4 Giu 2018
Hi
p00=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p01=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p02=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
for i=1:length(p00)
for j=1:length(p01)
for k=1:length(p02)
p03=1-p00(1,i)-p01(1,j)-p02(1,k)
H(i,j,k) = real((-p00(i).*log2(p00(i))-(p01(j)).*log2(p01(j))-p02(k).*log2((p02(k)))-p03*log2(p03)))
end
end
end
is this what you are trying to calculate?
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!