Azzera filtri
Azzera filtri

How to delete multiple row and column in matrix A and Delete row and column specified in matrix B?????????????/

17 visualizzazioni (ultimi 30 giorni)
A =[
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7];
size(A)= 18 * 7
B=[2;3;4;5;7;9;]
size(B)= 6 * 1
The deleted row and column specified in matrix B........
I want to delete in A matrix ........
B(1)=2 ie 2 row and 2 column delete in matrix A
B(2)=3 ie 3 row and 3 column delete in matrix A
B(3)=4 ie 4 row and 4 column delete in matrix A
and so on............
  1 Commento
Rik
Rik il 12 Ago 2018
You can't delete single elements in arrays. You could replace them by NaN, but as you didn't explain what you want to do, I don't know if that would fit your needs.

Accedi per commentare.

Risposte (1)

dpb
dpb il 12 Ago 2018
Modificato: dpb il 12 Ago 2018
On the assumption it really is to remove the full row/column, not the individual element, "Dead ahead" is sometimes the simplest...
B=sort(B,'descend'); % will need to remove rows/columns from back going forward
for i=1:length(B)
A(B(i),:)=[]; % remove row
A(:,B(i))=[]; % remove column
end
NB: Your example above will fail as B(end)>size(A,2)
If the intent is to remove the row even if there isn't such a column, then incorporate error testing or just use a try...catch block to skip the addressing error.
for i=1:length(B)
try, A(B(i),:)=[]; catch,end % remove row if extant, don't error
try, A(:,B(i))=[]; catch,end % ditto remove column
end

Categorie

Scopri di più su Performance and Memory in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by