how to find out how many times a number apears in a 2D matrix ? which function to use?
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Hey,
how can I find how many time a numbers appears in an 2D matrix for example:
If I have a matrix
x=[1,3,4;2,2,1;2,2,1]
number 2 appears 4 times
numger 1 appears 2 times
number 3 appears 1 time
Desired output:
22 1 3
22 1
1 Commento
Image Analyst
il 7 Gen 2019
Modificato: Image Analyst
il 7 Gen 2019
You can't have an array with ragged right edge. Arrays must be rectangular. What do you want in the space below the 3? Or else you could have a 1-by-3 cell array, ca where
ca{1} = [2, 2; 2, 2];
ca{2} = [1;1];
ca{3} = 3;
Is that what you want?
Anyway, 1 appears 3 times, not 2 times, and what about 4? Why is 4 not in your desired output?
Risposta accettata
madhan ravi
il 5 Gen 2019
n=2; % number to be tested
nnz(ismember(x,n))
2 Commenti
madhan ravi
il 7 Gen 2019
Modificato: madhan ravi
il 7 Gen 2019
Try the below , a in result represent unique numbers and the corresponding histc() shows how many times they occur in the matrix:
a = unique(x);
result = [a histc(x(:),a)]
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