how to find the index for the following code

If A=1:10,%A= 1 2 3 4 5 6 7 8 9 10

But I want to display the index of A using for loop.

Could anyone help me to solve the issue.

[Stephen23]

"But I want to display the index of A using for loop."

What does this mean? Please show us the expected output.

[jaah navi]

when A=1:10 it displays the number from 1 to 10.

I want to have the expected output in the following manner.

when A=1,I want to display one number with respect to first element.

when A=2,i want to display one number with respect to second element.

...

when A=10,i want to display one number with respect to last element.

could you please help me on this.

[Rik]

Can't you just use A as an index?

someData=[5 8 7 4 6 9 3 10 7 2];
A=5;
disp(someData(5))%shows the 5th element (6 in this case)

%or in a loop:
for A=1:10
    disp(someData(A))
end

Answer 1

[madhan ravi]

“But I want to display the index of A using for loop”

You don’t need one , see the documentation of fprintf().

Values=rand(1,10); % example data
A=1:numel(Values); %indices
fprintf('When A = %d the value is %d\n',[A;Values])