Using parametric equations in terms of theta1 and theta2 to plot a point A for a range of angles

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I am trying to write a code that uses two parametric equations of x and y, which depend on the variables theta1 and theta2. Then I have to produce a plot of x Vs y for a range of values of theta1 and theta2. I am stuck how can I do this?
Bellow is my current code to display the coordinate of this point defined by the parametric equations a and b (btw this code doesn't work for reasons that I do not understand). Now I have to use these functions to produce an array that will plot the x,y coordinates over a range of values of theta1 (20 to 80 deg in increments of 0,5) and of theta2 (90 to 30 deg in increments if 0,5).
Thanks in advance for any help! Started Matlab a few weeks ago :) (I attached a screenshot of the question)
n1 = input('Enter θ1: ');
n2 = input('Enter θ2: ');
function a = first_calc(n1,n2)
a = 0.6*cosd(n1) + 0.2*cosd(n1-n2);
end
function b = second_calc(n1,n2)
b = 0.6*sind(n1) + 0.2*sind(n1-n2);
end
fprintf('The value for x is %g, and that of y is g%\n' a,b);

Risposta accettata

Krishna Zanwar
Krishna Zanwar il 26 Feb 2019
Hey Raphael,
In this case you have defined a function but not called it in your script and so you are getting an error while printing the a and b variables.
You can just call the function in your script as
a = first_calc(n1,n2);
b = second_calc(n1,n2);
You can get the example on it here.
Secondly to create an array –
Theta1=20:0.5:80;
Theta2=90:-0.5:30;
You can learn how to use the plot function here.
  6 Commenti
Krishna Zanwar
Krishna Zanwar il 1 Mar 2019
I meant just put this in the script .
theta1=20:0.5:80;
theta2=90:-0.5:30;
a = 0.6*cosd(theta1) + 0.2*cosd(theta1-theta2);
b = 0.6*sind(theta1) + 0.2*sind(theta1-theta2);
plot(a,b)
xlabel('x Coordinate of Point A');
ylabel('Y Coordinate of Point A');
It will give you the same response.
Raphael Aubry
Raphael Aubry il 1 Mar 2019
Hey thanks a lot Krishna! it works very well now - things need to be kept very simply it seems and then it works. Bellow is a photo of the code and graph

Accedi per commentare.

Più risposte (1)

Krishna Zanwar
Krishna Zanwar il 27 Feb 2019
Hey Raphael,
Since Matlab does direct calculations of Vectors you dont need a for loop for this problem.
theta1=20:0.5:80;
theta2=90:-0.5:30;
a = 0.6*cosd(theta1) + 0.2*cosd(theta1-theta2)
b = 0.6*sind(theta1) + 0.2*sind(theta1-theta2)
Hope it helps.

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