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counting no .of temperature less than 32 in array

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Abhishek singh
Abhishek singh il 3 Apr 2019
Chiuso: madhan ravi il 30 Ago 2020
function numfreeze = freezing(v)
count = 0;
i =v()
j = 32
if i < 32
count = count+1
numfreeze = count
else
end
  1 Commento
Abhishek singh
Abhishek singh il 3 Apr 2019
geeting errror
i =
45 21 32 31 51 12
j =
32
Output argument "numfreeze" (and maybe others) not assigned during call to "freezing".

Risposte (6)

Ngei Katumo
Ngei Katumo il 22 Ago 2019
function w = freezing (A)
w = sum (logical (A(A<32)));
end

madhan ravi
madhan ravi il 3 Apr 2019
v=[45 21 32 31 51 12];
threshold=32;
numfreeze = freezing(v,threshold) % function call
function numfreeze = freezing(v,threshold) % function definition
numfreeze = nnz(v<threshold);
end
  6 Commenti
Image Analyst
Image Analyst il 11 Giu 2019
You mean freezing.m, since that's what was asked.

Nazneen Sayyad
Nazneen Sayyad il 10 Giu 2019
Write a function called freezing that takes a vector of numbers that correspond to daily low temperatures in Fahrenheit. Return numfreeze, the number of days with sub freezing temperatures (that is, lower than 32 F) without using loops. Here is an example run:
numfreeze = freezing([45 21 32 31 51 12])
numfreeze =
3
function numfreeze = freezing(A)
B=A(A<32);
numfreeze=numel(B);
end

Ajith Thomas
Ajith Thomas il 19 Lug 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
no_logical_values=lowerthan_32(lowerthan_32>=0);
numfreeze=length(no_logical_values);
end
  1 Commento
Ajith Thomas
Ajith Thomas il 19 Lug 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
numfreeze=numel(lowerthan_32);
end

Roshan Singh
Roshan Singh il 15 Set 2019
function numfreeze = freezing(x)
f = x(x<32);
numfreeze = length(f);
end

MADHURJYA DAS
MADHURJYA DAS il 30 Ago 2020
function numfreeze=freezing(A)
x=(A<32);
numfreeze=sum(x(:));
end

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Release

R2015b

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